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Homogeneous symmetric trace-positive sextics with vanishing abelianization are sums of Hermitian squares and commutators

Keren, Daniel
arXiv (All) · Papers
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combinatoricsoperator-algebrasrings-and-algebras
Let $\mathbb{R}\langle X,Y\rangle$ be the free algebra on two symmetric letters. A polynomial is trace-positive if it has non-negative trace on every pair of real symmetric matrices, and it lies in the cone $Θ$ if it is cyclically equivalent to a sum of Hermitian squares. Burgdorf and Klep proved th
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